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Post by Admin on Aug 11, 2016 15:50:05 GMT
Gary
From readings of Section II Spherical Geometry, and attempting exercise 5, I feel fairly confident that I have discovered a couple of errors on page 286. The second error results from the first. The first error is in the fourth equation on the page, which I think should be $$|f'(z)|=\frac{\Lambda(z)}{\Lambda[f(z)]}$$ and then (17) which should be $$|f'(z)|=\frac{1+|f(z)|^2}{1+|z|^2}.$$ The reason I think this is because from the third equation on the page we have $$\frac{d\tilde{s}}{ds}=\frac{\Lambda(z)}{\Lambda[f(z)]}$$ and since $$\frac{d\tilde{s}}{ds}=\frac{|d\tilde{z}|}{|dz|}=|f'(z)|$$ we must have $$|f'(z)|=\frac{\Lambda(z)}{\Lambda[f(z)]},$$ and the error in (17) follows from this. This also ties in with the fact that $\Lambda$ is a real number.
What do you think?
Vasco
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Gary
GaryVasco
Posts: 3,352
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Post by Gary on Aug 15, 2016 21:49:25 GMT
Vasco,
From the discussion on p. 284, $ds=|dz|$, but $dz = e^{i\phi}ds$, so it is possible that dz = -ds. Since $d\widehat{s}$ is a "distance" (line 1, para. 2), I would assume that it must be a positive real number. Then from (14) and (15), $\Lambda(z) = d\widehat{s}/ds$ must also be a positive number. The derivation on p. 286 is conformal, so (15) applies. I must assume that $d\widehat{z} = f'(z)dz$ is correct. Then, the absolute sign on f'(z) is necessary for the following to work:
$\hspace{5em}|f'(z)| = \frac{|d\tilde{z}|}{|dz|} = \frac{d\tilde{s}}{ds} = \frac{\Lambda(z)}{\Lambda{[\tilde{z}]}} = \frac{\Lambda(z)}{\Lambda{[f(z)]}}$,
which for $S = \Sigma$ and using (16) should be $\frac{1+|f(z)|^2}{1+|z|^2}$.
I agree with your correction.
Gary
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