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Post by Admin on Apr 7, 2017 15:16:15 GMT
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Gary
GaryVasco
Posts: 3,352 
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Post by Gary on Apr 20, 2017 21:41:48 GMT
Vasco, Here is my answer. nh.ch7.ex11.pdf (88.09 KB) I don't know that I used a very good method of determining absolute values of f and g, so I will be interested to read yours. Gary |
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Post by Admin on Apr 21, 2017 5:00:09 GMT
Gary
Looking at your document, I think there is a typo:
On line 1 of your answer you write $x^2+y^2=2, y=\sqrt{x^2-2}$. Since $|z|=2$, this should be $x^2+y^2=4, y=\sqrt{x^2-4}$.
Vasco
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Gary
GaryVasco
Posts: 3,352
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Post by Gary on Apr 21, 2017 15:17:04 GMT
Gary Looking at your document, I think there is a typo: On line 1 of your answer you write $x^2+y^2=2, y=\sqrt{x^2-2}$. Since $|z|=2$, this should be $x^2+y^2=4, y=\sqrt{x^2-4}$. Vasco Vasco, It is either a typo or a bit of fog. It's hardly needed, but it does set the stage for the next line. Gary |
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