Post by tubegeek on Apr 1, 2019 18:32:09 GMT
Chapter 1, Ex. 2 explained here:
CH1 Ex 2
This should read
By the third line of the expansion in the solution it is back to the correct expression.
Thank you for this interesting site. I have tried to work my way through VCA before and I hope to do it this time with the help of this resource.
CH1 Ex 2
"Substituting x = s + t into the cubic equation x3 = 3px + 2q gives:
(s + t)3 = 3pq(s + t) + 2q"
(s + t)3 = 3pq(s + t) + 2q"
This should read
"Substituting x = s + t into the cubic equation x3 = 3px + 2q gives:
(s + t)3 = 3p(s + t) + 2q"
(s + t)3 = 3p(s + t) + 2q"
By the third line of the expansion in the solution it is back to the correct expression.
Thank you for this interesting site. I have tried to work my way through VCA before and I hope to do it this time with the help of this resource.
