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Post by Admin on Jun 27, 2023 5:46:15 GMT
Mondo
It's clear from your diagram that any change in $(z-a)$ causes the same change in $z$
Vasco
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Post by Admin on Jun 27, 2023 6:37:38 GMT
Mondo
Especially if you draw a line joining $z'$ and $a$. No need for a circle or infinitesimals.
Vasco
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Post by mondo on Jun 27, 2023 6:55:13 GMT
The thing is author is talking about $dz$ but strictly speaking, this is not what rotates around the circle. I mean we can call it whatever but $dz$ confused me as it suggest me a vector $z$ from origin to a point on a circle is rotating. This is not the case - it is $(z-a)$ or $re^{i\theta}$ that rotates around that circle.
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Post by Admin on Jun 27, 2023 7:47:52 GMT
Mondo
OK. there's more than one way to think about it.
Vasco
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