Post by mondo on Jul 8, 2023 22:19:49 GMT
At the bottom of page 485 author writes:
So the way I understand it is, the polya vector field of $\frac{1}{\overline{z}}$ means that we are dealing with a vector field $H = \frac{1}{z}$. However, how can we say it is a source of strength $2\pi$ without knowing what $L$, the path of integration is? If it is a circle then it should be $2\pi r|V|$ as described on top of page $455$.
But the Polya vector field $\frac{1}{\overline{z}}$ is an old friend - it is a source of strength $2\pi$
So the way I understand it is, the polya vector field of $\frac{1}{\overline{z}}$ means that we are dealing with a vector field $H = \frac{1}{z}$. However, how can we say it is a source of strength $2\pi$ without knowing what $L$, the path of integration is? If it is a circle then it should be $2\pi r|V|$ as described on top of page $455$.
